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x^2-3.4x=0
a = 1; b = -3.4; c = 0;
Δ = b2-4ac
Δ = -3.42-4·1·0
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.4)-\sqrt{11.56}}{2*1}=\frac{3.4-\sqrt{11.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.4)+\sqrt{11.56}}{2*1}=\frac{3.4+\sqrt{11.56}}{2} $
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